Divisibility Test
Title: Special Number Delivery
Class: 5
Topic: Divisibility Tests
Duration: 15 Minutes
Number of Students: 5
Props Required: • A small delivery bag • Number cards (15,
24, 30, 45) • Four house cards labelled House 2, House 3, House 5, House 10
Roles: Student 1 – Delivery Boy/Girl Student 2 – House 2
Owner Student 3 – House 3 Owner Student 4 – House 5 Owner Student 5 – House 10
Owner
Introduction
The Delivery Boy has special number parcels. Each house
accepts parcels only if they follow its divisibility rule.
Activity Script
(Student 1 enters carrying a delivery bag.)
Student 1: "Good morning! I have special number
parcels. Please help me deliver them to the correct houses."
All House Owners: "Welcome! We will accept only the
parcels that follow our house rules."
Round 1 – Parcel Number 24
Student 1: "I have Parcel 24. Which house should
receive it?"
House 2 Owner: "Send it here! 24 is even."
House 3 Owner: "Wait! 2 + 4 = 6. It belongs to my house
too."
House 5 Owner: "Sorry, it doesn't end in 0 or 5."
House 10 Owner: "It doesn't end in 0, so not my
parcel."
Student 1: "Parcel 24 has two addresses today!"
(Delivery student walks dramatically to both houses and
hands over the parcel.)
Round 2 – Parcel Number 15
Student 1: "Next parcel is Number 15."
House 2 Owner: "Not for me."
House 3 Owner: "1 + 5 = 6. Deliver it here."
House 5 Owner: "It ends in 5. I want it too."
House 10 Owner: "Not my parcel."
Student 1: "Parcel 15 is going to Houses 3 and 5."
Round 3 – Parcel Number 30
Student 1: "Oh! This parcel looks important. It is
Number 30."
House 2 Owner: "I'll take it."
House 3 Owner: "I'll take it too."
House 5 Owner: "Me too!"
House 10 Owner: "And me!"
Student 1: "Oh no! Everyone wants this parcel!"
(All house owners raise their hands excitedly.)
Student 1: "This is a VIP parcel. It belongs to all
four houses."
Final Challenge
Student 1: "I have a secret parcel. It belongs to House
2 and House 3 but not to House 5 or House 10. Can you guess the number?"
House 2 Owner: "18!"
House 3 Owner: "24!"
House 5 Owner: "42!"
Student 1: "Excellent! All these answers are
correct."
Conclusion
All Students Together: "Numbers can have more than one
address. Divisibility tests help us deliver every parcel to the correct house
quickly and correctly!"
HCF
Topic: HCF (Highest Common Factor)
Duration: 15–20 Minutes
Number of Students: 4
Props Required: • 12 Balls (or paper cut-outs) • 18 Chocolates (paper cut-outs) • 24 Toys (paper cut-outs) • Small gift bags/envelopes
Characters: Student 1 – Ravi Student 2 – Ball Manager Student 3 – Chocolate Manager Student 4 – Toy Manager
Introduction
Ravi is organizing a Children's Day celebration. He has 12 balls, 18 chocolates, and 24 toys. He wants to make gift packs so that: • Every gift pack is exactly the same. • No item is left over.
Can his friends help him?
Activity Script
Ravi: "Hello friends! I want to make gift packs for children. Every gift pack should have the same number of balls, chocolates, and toys. Can you help me?"
Ball Manager: "You have 12 balls. Let's see how many equal groups we can make."
Chocolate Manager: "You have 18 chocolates. We must divide them equally too."
Toy Manager: "You have 24 toys. No toys should be left over."
Ravi: "Let's find a number that can divide all three quantities."
Ball Manager: "12 can be divided into 1, 2, 3, 4, 6, and 12 groups."
Chocolate Manager: "18 can be divided into 1, 2, 3, 6, 9, and 18 groups."
Toy Manager: "24 can be divided into 1, 2, 3, 4, 6, 8, 12, and 24 groups."
Ravi: "Which is the greatest number common to all?"
All Managers Together: "6!"
Ravi: "That means I can make 6 identical gift packs."
Ball Manager: "Each gift pack will get 12 ÷ 6 = 2 balls."
Chocolate Manager: "Each gift pack will get 18 ÷ 6 = 3 chocolates."
Toy Manager: "Each gift pack will get 24 ÷ 6 = 4 toys."
Ravi: "Wonderful! Every child will receive the same gift pack."
(All students pretend to prepare six gift packs.)
Final Discussion
Ravi: "What did we find today?"
Ball Manager: "We found the Highest Common Factor."
Chocolate Manager: "It is the greatest number that divides all the quantities exactly."
Toy Manager: "The HCF of 12, 18, and 24 is 6."
All Together: "Using HCF helps us divide things into equal groups without any leftovers!"
Conclusion
Ravi successfully made 6 identical gift packs. Each pack contained: • 2 Balls • 3 Chocolates • 4 Toys
Therefore, HCF (12, 18, 24) = 6.
LCM
Topic: LCM (Least Common Multiple)
Duration: 15–20 Minutes
Number of Students: 5
Props Required: • Four coloured circles/cards – Red, Blue, Green, Yellow • A stopwatch/mobile timer • Colour badges
Characters: Student 1 – Narrator Student 2 – Red Light Student 3 – Blue Light Student 4 – Green Light Student 5 – Yellow Light
Situation
At a park, four decorative lights glow at different intervals:
• Red Light glows every 2 seconds. • Blue Light glows every 3 seconds. • Green Light glows every 4 seconds. • Yellow Light glows every 6 seconds.
They all glow together at the start. The question is:
"When will they glow together again?"
Activity Script
Narrator: "Welcome to the Glowing Lights Show! All the lights glow together now."
(All four students clap once together.)
Red Light: "I glow every 2 seconds."
Blue Light: "I glow every 3 seconds."
Green Light: "I glow every 4 seconds."
Yellow Light: "I glow every 6 seconds."
Narrator: "Let's find when they will all glow together again."
Red Light: "My glow times are 2, 4, 6, 8, 10, 12..."
Blue Light: "My glow times are 3, 6, 9, 12..."
Green Light: "My glow times are 4, 8, 12..."
Yellow Light: "My glow times are 6, 12..."
Narrator: "I see a common number!"
All Lights: "12!"
Narrator: "That means after 12 seconds, all four lights will glow together again."
(All students clap together again.)
Final Discussion
Narrator: "What did we find today?"
Red Light: "We found the first common multiple."
Blue Light: "It is called the Least Common Multiple."
Green Light: "The LCM of 2, 3, 4 and 6 is 12."
Yellow Light: "So all the lights glow together after 12 seconds."
All Together: "LCM helps us find when repeating events happen together again!"
Conclusion
LCM (2, 3, 4, 6) = 12
Therefore, the Red, Blue, Green and Yellow lights will glow together again after 12 seconds.
