Natural Numbers and Whole Numbers Class 6 Selina Solutions

Shaleen Shekhar
0
Class 6 Concise Mathematics Selina

Natural Numbers and Whole Numbers

Interactive, step-by-step solutions for Exercises 3(A) to 3(E), including number properties, operations, patterns, magic squares and objective questions.

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Whole numbers0, 1, 2, 3, ...
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01

Exercise 3(A)

5 fully explained questions

Question 1Exercise 3(A)

Fill in the blanks:

(i) Smallest natural number is

(ii) Smallest whole number is

(iii) Largest natural number is

(iv) Largest whole number is

(v) All natural numbers are

(vi) All whole numbers are not

(vii) Successor of 4099 is

(viii) Predecessor of 4330 is

View step-by-step answerOpen

(i) The smallest natural number is 1.

(ii) The smallest whole number is 0.

(iii) The largest natural number is not possible (natural numbers are infinite).

(iv) The largest whole number is not possible (whole numbers are infinite).

(v) All natural numbers are whole numbers.

(vi) All whole numbers are not natural numbers.

(vii) Successor of 4099 = 4099 + 1 = 4100.

(viii) Predecessor of 4330 = 4330 - 1 = 4329.

Question 2Exercise 3(A)

State true or false:

(i) Whole numbers are closed for addition.

(ii) If a and b are any two whole numbers, then a + b is not a whole number.

(iii) If a and b are any two whole numbers, then a + b = b + a.

(iv) 0 + 18 = 18 + 0.

(v) Addition of whole numbers is associative.

(vi) 10 + 12 + 16 = (10 + 12) + 16 = 10 + (12 + 16).

View step-by-step answerOpen

(i) True. The sum of two whole numbers is always a whole number, so whole numbers are closed for addition.

(ii) False. By the closure property of addition, a + b is always a whole number.

(iii) True. Addition of whole numbers is commutative, so a + b = b + a.

(iv) True. By the commutative property, 0 + 18 = 18 + 0 = 18.

(v) True. Addition of whole numbers is associative.

(vi) True. By the associative property, (10 + 12) + 16 = 10 + (12 + 16) = 38.

Question 3Exercise 3(A)

Fill in the blanks:

(i) 54 + 234 = 234 +

(ii) 332 + 497 = + 332

(iii) 286 + 0 =

(iv) 286 × 1 =

(v) a + (b + c) = (a + ) + c

View step-by-step answerOpen

(i) By the Commutative Property of Addition: a + b = b + a.

54 + 234 = 234 + 54.

(ii) By the Commutative Property of Addition: a + b = b + a.

332 + 497 = 497 + 332.

(iii) By the Additive Identity property, adding 0 to a whole number gives the number itself.

286 + 0 = 286.

(iv) By the Multiplicative Identity property, multiplying a whole number by 1 gives the number itself.

286 × 1 = 286.

(v) By the Associative Property of Addition: a + (b + c) = (a + b) + c.

a + (b + c) = (a + b) + c.
Question 4Exercise 3(A)

Verify that:

(i) 3 + (5 + 4) = (3 + 5) + 4

(ii) 8 × (8 + 0) = 8 × 8 + 8 × 0

(iii) (7 + 6) × 10 = 7 × 10 + 6 × 10

(iv) (15 - 12) × 18 = 15 × 18 - 12 × 18

(v) 16 + 0 = 16

(vi) 23 + (-23) = 0

View step-by-step answerOpen

(i) 3 + (5 + 4) = (3 + 5) + 4

L.H.S.3 + (5 + 4) = 3 + 9 = 12.
R.H.S.(3 + 5) + 4 = 8 + 4 = 12.

Since L.H.S. = R.H.S., the result is verified.

(ii) 8 × (8 + 0) = 8 × 8 + 8 × 0

L.H.S.8 × (8 + 0) = 8 × 8 = 64.
R.H.S.8 × 8 + 8 × 0 = 64 + 0 = 64.

Since L.H.S. = R.H.S., the result is verified.

(iii) (7 + 6) × 10 = 7 × 10 + 6 × 10

L.H.S.(7 + 6) × 10 = 13 × 10 = 130.
R.H.S.7 × 10 + 6 × 10 = 70 + 60 = 130.

Since L.H.S. = R.H.S., the result is verified.

(iv) (15 - 12) × 18 = 15 × 18 - 12 × 18

L.H.S.(15 - 12) × 18 = 3 × 18 = 54.
R.H.S.15 × 18 - 12 × 18 = 270 - 216 = 54.

Since L.H.S. = R.H.S., the result is verified.

(v) 16 + 0 = 16

L.H.S.16 + 0 = 16 = R.H.S.

By the Additive Identity property, the result is verified.

(vi) 23 + (-23) = 0

L.H.S.23 + (-23) = 23 - 23 = 0 = R.H.S.

The result is verified.

Question 5Exercise 3(A)

State true or false:

(i) The sum of two odd numbers is an odd number.

(ii) The sum of two odd numbers is an even number.

(iii) The sum of two even numbers is an even number.

(iv) The sum of two even numbers is an odd number.

(v) The sum of an even number and an odd number is odd number.

(vi) Every whole number is a natural number.

(vii) Every natural number is a whole number.

(viii) Every whole number + 0 = The whole number itself.

(ix) Every whole number × 1 = The whole number itself.

(x) Commutativity and associativity are properties of natural numbers and whole numbers both.

(xi) Commutativity and associativity are properties of addition for natural numbers and whole numbers both.

(xii) If x is a whole number then -x is also a whole number.

View step-by-step answerOpen

(i) False. The sum of two odd numbers is an even number. For example, 3 + 5 = 8.

(ii) True. The sum of two odd numbers is an even number. For example, 7 + 9 = 16.

(iii) True. The sum of two even numbers is an even number. For example, 4 + 6 = 10.

(iv) False. The sum of two even numbers is an even number, not an odd number.

(v) True. The sum of an even number and an odd number is an odd number. For example, 4 + 3 = 7.

(vi) False. 0 is a whole number but it is not a natural number, so every whole number is not a natural number.

(vii) True. Every natural number is a whole number.

(viii) True. Adding 0 to any whole number gives the number itself (additive identity).

(ix) True. Multiplying any whole number by 1 gives the number itself (multiplicative identity).

(x) False. Commutativity and associativity are not properties of every operation (for example, they do not hold for subtraction and division). The statement is incomplete as it does not mention the operation.

(xi) True. For the operation of addition, both commutativity and associativity hold for natural numbers as well as whole numbers.

(xii) False. If x is a whole number, then -x is a negative number, and negative numbers are not whole numbers.

02

Exercise 3(B)

6 fully explained questions

Question 1Exercise 3(B)

Consider two whole numbers a and b such that a is greater than b.

(i) Is a - b a whole number? Is this result always true?

(ii) Is b - a a whole number? Is this result always true?

View step-by-step answerOpen

(i) Since a is greater than b, the difference a - b is a positive number.

So, a - b is a whole number, and yes, this result is always true (whenever a is greater than b).

(ii) Since a is greater than b, the difference b - a is a negative number, and negative numbers are not whole numbers.

So, b - a is not a whole number, and yes, this result is always true (whenever a is greater than b, b - a is always negative).

Question 2Exercise 3(B)

Write the identity number, if possible for subtraction of whole numbers.

View step-by-step answerOpen

For any whole number x, we have x - 0 = x, but 0 - x ≠ x.

An identity element must give the same number when applied from both sides, but for subtraction 0 works only from the right side and not from the left.

Hence, the identity number for subtraction of whole numbers is not possible (it does not exist).

Question 3Exercise 3(B)

Fill in the blanks:

(i) 12 × (9 - 6) = =

(ii) 12 × 9 - 12 × 6 = =

(iii) Is 12 × (9 - 6) = 12 × 9 - 12 × 6?

(iv) Is this type of result always true?

View step-by-step answerOpen

(i) 12 × (9 - 6) = 12 × 3 = 36.

(ii) 12 × 9 - 12 × 6 = 108 - 72 = 36.

(iii) Both results are equal to 36, so yes, 12 × (9 - 6) = 12 × 9 - 12 × 6.

(iv) Yes. By the Distributive Law of Multiplication over Subtraction, this type of result is always true.

Question 4Exercise 3(B)

Fill in the blanks:

(i) (16 - 8) × 24 = =

(ii) 16 × 24 - 8 × 24 = - =

(iii) Is (16 - 8) × 24 = 16 × 24 - 8 × 24?

(iv) Is this type of result always true?

View step-by-step answerOpen

(i) (16 - 8) × 24 = 8 × 24 = 192.

(ii) 16 × 24 - 8 × 24 = 384 - 192 = 192.

(iii) Both results are equal to 192, so yes, (16 - 8) × 24 = 16 × 24 - 8 × 24.

(iv) Yes. By the Distributive Law of Multiplication over Subtraction, this type of result is always true.

Question 5Exercise 3(B)

Find the difference between the largest number of four digits and the smallest number of six digits.

View step-by-step answerOpen

The largest number of four digits = 9999.

The smallest number of six digits = 100000.

Difference = 100000 - 9999 = 90001.

Hence, the required difference is 90001.

Question 6Exercise 3(B)

Find the difference between the smallest number of eight digits and the largest number of five digits.

View step-by-step answerOpen

The smallest number of eight digits = 10000000.

The largest number of five digits = 99999.

Difference = 10000000 - 99999 = 9900001.

Hence, the required difference is 9900001.

03

Exercise 3(C)

6 fully explained questions

Question 1Exercise 3(C)

Fill in the blanks:

(i) 42 × 0 =

(ii) 592 × 1 =

(iii) 328 × 573 = × 328

(iv) 229 × = 578 × 229

(v) 32 × 15 = 32 × 6 + 32 × 7 + 32 ×

(vi) 23 × 56 = 20 × 56 + × 56

(vii) 83 × 54 + 83 × 16 = 83 × () = 83 × =

(viii) 98 × 273 - 75 × 273 = () × 273 = × 273

View step-by-step answerOpen

(i) Any number multiplied by 0 gives 0.

42 × 0 = 0.

(ii) Any number multiplied by 1 gives the number itself.

592 × 1 = 592.

(iii) By the Commutative Property of Multiplication: a × b = b × a.

328 × 573 = 573 × 328.

(iv) By the Commutative Property of Multiplication: a × b = b × a.

229 × 578 = 578 × 229.

(v) Since 6 + 7 + 2 = 15, we have:

32 × 15 = 32 × 6 + 32 × 7 + 32 × 2.

(vi) Since 23 = 20 + 3, we have:

23 × 56 = 20 × 56 + 3 × 56.

(vii) Using the Distributive Law of Multiplication over Addition:

83 × 54 + 83 × 16 = 83 × (54 + 16) = 83 × 70 = 5810.

(viii) Using the Distributive Law of Multiplication over Subtraction:

98 × 273 - 75 × 273 = (98 - 75) × 273 = 23 × 273.
Question 2Exercise 3(C)

Evaluate (using distributive property):

(i) 984 × 102

(ii) 385 × 1004

(iii) 446 × 10002

View step-by-step answerOpen

(i) 984 × 102

Therefore984 × (100 + 2)

Using the Distributive Law of Multiplication over Addition:

Therefore984 × 100 + 984 × 2
Therefore98400 + 1968
Therefore100368.

Hence, 984 × 102 = 100368.

(ii) 385 × 1004

Therefore385 × (1000 + 4)

Using the Distributive Law of Multiplication over Addition:

Therefore385 × 1000 + 385 × 4
Therefore385000 + 1540
Therefore386540.

Hence, 385 × 1004 = 386540.

(iii) 446 × 10002

Therefore446 × (10000 + 2)

Using the Distributive Law of Multiplication over Addition:

Therefore446 × 10000 + 446 × 2
Therefore4460000 + 892
Therefore4460892.

Hence, 446 × 10002 = 4460892.

Question 3Exercise 3(C)

Evaluate using properties:

(i) 548 × 98

(ii) 924 × 988

View step-by-step answerOpen

(i) 548 × 98

Therefore548 × (100 - 2)

Using the Distributive Law of Multiplication over Subtraction:

Therefore548 × 100 - 548 × 2
Therefore54800 - 1096
Therefore53704.

Hence, 548 × 98 = 53704.

(ii) 924 × 988

Therefore924 × (1000 - 12)

Using the Distributive Law of Multiplication over Subtraction:

Therefore924 × 1000 - 924 × 12
Therefore924000 - 11088
Therefore912912.

Hence, 924 × 988 = 912912.

Question 4Exercise 3(C)

Evaluate using properties:

(i) 679 × 8 + 679 × 2

(ii) 284 × 12 - 284 × 2

(iii) 55873 × 94 + 55873 × 6

(iv) 7984 × 15 - 7984 × 5

(v) 8324 × 1945 - 8324 × 945

(vi) 3333 × 987 + 13 × 3333

View step-by-step answerOpen

(i) 679 × 8 + 679 × 2

Using the Distributive Law of Multiplication over Addition: a × b + a × c = a × (b + c).

Therefore679 × (8 + 2)
Therefore679 × 10
Therefore6790.

Hence, 679 × 8 + 679 × 2 = 6790.

(ii) 284 × 12 - 284 × 2

Using the Distributive Law of Multiplication over Subtraction: a × b - a × c = a × (b - c).

Therefore284 × (12 - 2)
Therefore284 × 10
Therefore2840.

Hence, 284 × 12 - 284 × 2 = 2840.

(iii) 55873 × 94 + 55873 × 6

Using the Distributive Law of Multiplication over Addition:

Therefore55873 × (94 + 6)
Therefore55873 × 100
Therefore5587300.

Hence, 55873 × 94 + 55873 × 6 = 5587300.

(iv) 7984 × 15 - 7984 × 5

Using the Distributive Law of Multiplication over Subtraction:

Therefore7984 × (15 - 5)
Therefore7984 × 10
Therefore79840.

Hence, 7984 × 15 - 7984 × 5 = 79840.

(v) 8324 × 1945 - 8324 × 945

Using the Distributive Law of Multiplication over Subtraction:

Therefore8324 × (1945 - 945)
Therefore8324 × 1000
Therefore8324000.

Hence, 8324 × 1945 - 8324 × 945 = 8324000.

(vi) 3333 × 987 + 13 × 3333

Therefore3333 × 987 + 3333 × 13

Using the Distributive Law of Multiplication over Addition:

Therefore3333 × (987 + 13)
Therefore3333 × 1000
Therefore3333000.

Hence, 3333 × 987 + 13 × 3333 = 3333000.

Question 5Exercise 3(C)

Find the product of the:

(i) greatest number of three digits and smallest number of five digits.

(ii) greatest number of four digits and the greatest number of three digits.

View step-by-step answerOpen

(i) The greatest number of three digits = 999.

The smallest number of five digits = 10000.

Product = 999 × 10000 = 9990000.

Hence, the required product is 9990000.

(ii) The greatest number of four digits = 9999.

The greatest number of three digits = 999.

Product = 9999 × 999
Therefore9999 × (1000 - 1)
Therefore9999 × 1000 - 9999 × 1
Therefore9999000 - 9999
Therefore9989001.

Hence, the required product is 9989001.

Question 6Exercise 3(C)

Fill in the blanks:

(i) (437 + 3) × (400 - 3) = 397 × =

(ii) 66 + 44 + 22 = 11 × () = 11 × =

View step-by-step answerOpen

(i) Here, 437 + 3 = 440 and 400 - 3 = 397.

So, (437 + 3) × (400 - 3) = 440 × 397 = 397 × 440 [by commutative property]

Therefore397 × 440 = 174680.

(ii) Since 66 = 11 × 6, 44 = 11 × 4 and 22 = 11 × 2, using the distributive property:

Therefore66 + 44 + 22 = 11 × 6 + 11 × 4 + 11 × 2
Therefore11 × (6 + 4 + 2) = 11 × 12 = 132.
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04

Exercise 3(D)

4 fully explained questions

Question 1Exercise 3(D)

Show that:

(i) division of whole numbers is not closed.

(ii) any whole number divided by 1, always gives the number itself.

(iii) every non-zero whole number divided by itself gives 1 (one).

(iv) zero divided by any non-zero number is zero only.

(v) a whole number divided by 0 is not defined.

For each part, given above, give two suitable examples.

View step-by-step answerOpen

(i) Division of whole numbers is not closed because the result of dividing one whole number by another is not always a whole number.

Examples: 5 ÷ 8 and 12 ÷ 24 are not whole numbers, etc.

(ii) Any whole number divided by 1, always gives the number itself.

Examples: 5 ÷ 1 = 5, and 16 ÷ 1 = 16, etc.

(iii) Every non-zero whole number divided by itself gives 1.

Examples: 8 ÷ 8 = 1, and 12 ÷ 12 = 1, etc.

(iv) Zero divided by any non-zero whole number gives zero only.

Examples: 0 ÷ 6 = 0, and 0 ÷ a = 0, if a ≠ 0, etc.

(v) A whole number divided by 0 is not defined.

Examples: 7 ÷ 0 is not defined, and 16 ÷ 0 is not defined, etc.
Question 2Exercise 3(D)
If x is a whole number such that x ÷ x = x; state the value of x.
View step-by-step answerOpen

For every non-zero whole number, dividing it by itself gives 1, i.e. x ÷ x = 1.

So, x ÷ x = x means x = 1.

Hence, the value of x is 1.

Question 3Exercise 3(D)

Fill in the blanks:

(i) 987 ÷ 1 =

(ii) 0 ÷ 987 =

(iii) 336 - (888 ÷ 888) =

(iv) (23 ÷ 23) - (437 ÷ 437) =

View step-by-step answerOpen

(i) Any whole number divided by 1 gives the number itself.

987 ÷ 1 = 987.

(ii) Zero divided by any non-zero whole number gives 0.

0 ÷ 987 = 0.

(iii) Any non-zero whole number divided by itself gives 1.

Therefore888 ÷ 888 = 1
Therefore336 - (888 ÷ 888) = 336 - 1 = 335.

(iv) Any non-zero whole number divided by itself gives 1.

Therefore23 ÷ 23 = 1 and 437 ÷ 437 = 1
Therefore(23 ÷ 23) - (437 ÷ 437) = 1 - 1 = 0.
Question 4Exercise 3(D)

Which of the following statements are true?

(i) 12 ÷ (6 × 2) = (12 ÷ 6) × (12 ÷ 2)

(ii) a ÷ (b - c) = ab - ac

(iii) (a - b) ÷ c = ac - bc

(iv) (15 - 13) ÷ 8 = (15 ÷ 8) - (13 ÷ 8)

(v) 8 ÷ (15 - 13) = 815 - 813

View step-by-step answerOpen

(i)

L.H.S.12 ÷ (6 × 2) = 12 ÷ 12 = 1
R.H.S.(12 ÷ 6) × (12 ÷ 2) = 2 × 6 = 12

Since L.H.S. ≠ R.H.S., statement (i) is false.

(ii) Division is not distributive over subtraction when the divisor is a difference. In general, a ÷ (b - c) ≠ ab - ac.

Statement (ii) is false.

(iii) When a difference is divided by the same non-zero number:

a - bc = ac - bc

Statement (iii) is true.

(iv)

L.H.S.(15 - 13) ÷ 8 = 2 ÷ 8 = 28 = 14
R.H.S.158 - 138 = 28 = 14

Since L.H.S. = R.H.S., statement (iv) is true.

(v)

L.H.S.8 ÷ (15 - 13) = 8 ÷ 2 = 4
R.H.S.815 - 813 = -16195

Since L.H.S. ≠ R.H.S., statement (v) is false.

Statements (iii) and (iv) are true.
05

Exercise 3(E)

4 fully explained questions

Question 1Exercise 3(E)

For each pattern, given below, write the next three steps:

(i) 1 × 9 + 1 = 10

12 × 9 + 2 = 110
123 × 9 + 3 = 1110

(ii) 9 × 9 + 7 = 88

98 × 9 + 6 = 888
987 × 9 + 5 = 8888

(iii) 1 × 8 + 1 = 9

12 × 8 + 2 = 98
123 × 8 + 3 = 987

(iv) 111 ÷ 3 = 37

222 ÷ 6 = 37
333 ÷ 9 = 37
View step-by-step answerOpen

(i) The next three steps are:

1234 × 9 + 4 = 11110
12345 × 9 + 5 = 111110
123456 × 9 + 6 = 1111110

(ii) The next three steps are:

9876 × 9 + 4 = 88888
98765 × 9 + 3 = 888888
987654 × 9 + 2 = 8888888

(iii) The next three steps are:

1234 × 8 + 4 = 9876
12345 × 8 + 5 = 98765
123456 × 8 + 6 = 987654

(iv) The next three steps are:

444 ÷ 12 = 37
555 ÷ 15 = 37
666 ÷ 18 = 37
Question 2Exercise 3(E)

Complete each of the following magic squares.

(i)
67
59
84
(ii)
48
7
10
(iii)
162
10
4
View step-by-step answerOpen

In a magic square, every row, column and diagonal has the same total. For a 3 by 3 magic square, the magic sum is three times the centre number.

(i) Magic sum = 3 × 5 = 15

Row 16 + 7 + 2 = 15
Row 21 + 5 + 9 = 15
Row 38 + 3 + 4 = 15
672
159
834

(ii) Magic sum = 3 × 7 = 21

Rows4 + 9 + 8 = 21; 11 + 7 + 3 = 21; 6 + 5 + 10 = 21
498
1173
6510

(iii) Magic sum = 3 × 10 = 30

Rows16 + 2 + 12 = 30; 6 + 10 + 14 = 30; 8 + 18 + 4 = 30
16212
61014
8184
Question 3Exercise 3(E)

Study the matchstick pattern carefully.

Figure 1
Figure 2
Figure 3
Figure 4

(i) If n denotes the figure number and S denotes the number of matchsticks, find S in terms of n.

(ii) Find the number of matchsticks required for the 15th figure and the 40th figure.

(iii) Describe the pattern in words.

View step-by-step answerOpen

Each new figure adds one square that shares one side with the existing pattern. Therefore, every new figure needs 3 additional matchsticks.

Figure number (n)1234
Matchsticks (S)7101316
RuleS = 7 + 3(n - 1)
SimplifyS = 7 + 3n - 3 = 3n + 4
S = 3n + 4
15th figureS = 3 × 15 + 4 = 49 matchsticks
40th figureS = 3 × 40 + 4 = 124 matchsticks

In words, the number of matchsticks is 4 more than three times the figure number.

Question 4Exercise 3(E)

Observe the matchstick pattern and draw the next two figures.

Figure 1
Figure 2
Figure 3

(i) Draw figures 4 and 5.

(ii) Construct a table for the pattern.

(iii) If n denotes the figure number and L denotes the number of matchsticks, find L in terms of n.

(iv) Find the number of matchsticks in the 12th and 20th figures.

View step-by-step answerOpen

The next two figures are:

Figure 4
Figure 5
Figure number (n)12345
Matchsticks (L)246810

Each figure contributes 2 matchsticks, so the rule is:

L = 2n
12th figureL = 2 × 12 = 24 matchsticks
20th figureL = 2 × 20 = 40 matchsticks
06

Multiple Choice Question

10 fully explained questions

Question 1Multiple Choice Question

The whole number that does not have its predecessor is:

11
20
32
4100
View step-by-step answerOpen

The predecessor of a whole number is obtained by subtracting 1 from it.

The predecessor of 0 would be 0 - 1 = -1, which is not a whole number.

So, 0 is the only whole number that does not have a predecessor.

Hence, option 2 is the correct option.

Question 2Multiple Choice Question

The predecessor of ten thousand is:

110001
29999
31001
4999
View step-by-step answerOpen
Ten thousand = 10000.
Predecessor of 10000 = 10000 - 1 = 9999.

Hence, option 2 is the correct option.

Question 3Multiple Choice Question

The value of 43 × 27 + 43 × 73 is equal to:

14300
243000
33166
41234
View step-by-step answerOpen

Using the Distributive Law of Multiplication over Addition:

43 × 27 + 43 × 73 = 43 × (27 + 73)
= 43 × 100 = 4300.

Hence, option 1 is the correct option.

Question 4Multiple Choice Question

484 × 101 is equal to:

148848
244888
348884
448404
View step-by-step answerOpen
484 × 101 = 484 × (100 + 1)

Using the Distributive Law of Multiplication over Addition:

= 484 × 100 + 484 × 1
= 48400 + 484 = 48884.

Hence, option 3 is the correct option.

Question 5Multiple Choice Question

57 × 13 - 57 × 3 is equal to:

157 × 16
257 × 10
3none of these
View step-by-step answerOpen

Using the Distributive Law of Multiplication over Subtraction:

57 × 13 - 57 × 3 = 57 × (13 - 3) = 57 × 10.

Hence, option 2 is the correct option.

Question 6Multiple Choice Question

(17 ÷ 17) - (97 ÷ 97) is equal to:

11
22
30
4Can't be determined.
View step-by-step answerOpen

Every non-zero whole number divided by itself gives 1.

(17 ÷ 17) - (97 ÷ 97) = 1 - 1 = 0.

Hence, option 3 is the correct option.

Question 7Multiple Choice Question

The number line for the whole numbers between 3 and 7 is:

3 4 5 6 7
View step-by-step answerOpen

The whole numbers between 3 and 7 are 4, 5 and 6.

The correct number line is the one in which only the points 4, 5 and 6 are marked between 3 and 7.

Hence, option 2 is the correct option.

Question 8Multiple Choice Question

The product of the greatest number of two digits and the smallest two digit number is:

1999
2990
3900
4980
View step-by-step answerOpen

The greatest number of two digits = 99.

The smallest number of two digits = 10.

Product = 99 × 10 = 990.

Hence, option 2 is the correct option.

Question 9Multiple Choice Question

If a ÷ a = a, then a is:

110
20
31
4none of these
View step-by-step answerOpen

For every non-zero whole number, a ÷ a = 1.

So, a ÷ a = a means a = 1.

Hence, option 3 is the correct option.

Question 10Multiple Choice Question

If 8 - (a - 7) = 8 + (4 - b), then:

1a = 4, b = 7
2a = -4, b = -7
3a = 4, b = -7
4a = -4, b = 7
View step-by-step answerOpen
L.H.S.8 - (a - 7) = 8 - a + 7 = 15 - a.
R.H.S.8 + (4 - b) = 8 + 4 - b = 12 - b.

So, 15 - a = 12 - b, which gives b - a = -3.

Substituting values from option 2:

Thereforea = -4 and b = -7 gives b - a = -7 - (-4) = -3.

Hence, option 2 is the correct option.

07

Statement I-II Type Questions

2 fully explained questions

Question 11Statement I-II Type Questions
Statement 1: For a whole number x, x - 0 = x implies 0 is identity element for subtraction.
Statement 2: For a whole number x, 0 - x = x implies 0 is identity element for subtraction.

Which of the following options is correct?

1Both the statements are true.
2Both the statements are false.
3Statement 1 is true, and statement 2 is false.
4Statement 1 is false, and statement 2 is true.
View step-by-step answerOpen

Statement 1: x - 0 = x shows that 0 is a right identity for subtraction. But 0 is an identity element only if it works from both the right and the left, i.e. 0 - x = x must also hold. Since 0 - x ≠ x, the number 0 is not the identity element for subtraction.

∴ Statement 1 is false.

Statement 2: 0 - x = x is not true for whole numbers (for example, 0 - 5 = -5 ≠ 5), so 0 is not the identity element for subtraction.

∴ Statement 2 is false.

Hence, option 2 is the correct option.

Question 12Statement I-II Type Questions
Statement 1: On subtracting a whole number from another whole number, the result is a natural number.
Statement 2: 15 and 25 are whole numbers, but 15 - 25 is not a natural number.

Which of the following options is correct?

1Both the statements are true.
2Both the statements are false.
3Statement 1 is true, and statement 2 is false.
4Statement 1 is false, and statement 2 is true.
View step-by-step answerOpen

Statement 1: Subtracting one whole number from another does not always give a natural number. For example, 5 - 5 = 0 (which is not a natural number) and 5 - 8 = -3 (which is not even a whole number).

∴ Statement 1 is false.

Statement 2: 15 - 25 = -10, which is a negative number and hence not a natural number. So the statement is correct.

∴ Statement 2 is true.

Hence, option 4 is the correct option.

08

Assertion Reason Type Questions

2 fully explained questions

Question 13Assertion Reason Type Questions
Assertion (A): Associativity properties of addition of natural numbers holds good.
Reason (R): For natural numbers a, b and c, a + (b + c) = (a + b) + c shows addition of natural numbers is associative.
1A is true, R is false.
2A is false, R is true.
3Both A and R are true.
4Both A and R are false.
View step-by-step answerOpen
Assertion (A): Addition of natural numbers is associative, i.e. for natural numbers a, b and c, a + (b + c) = (a + b) + c. So, the assertion is true.

Reason (R): The relation a + (b + c) = (a + b) + c is exactly the statement of the associative property of addition of natural numbers. So, the reason is true and it correctly explains the assertion.

Both A and R are true.

Hence, option 3 is the correct option.

Question 14Assertion Reason Type Questions
Assertion (A): 656 × 42 - 656 × 17 = 656 × (42 - 17) = 9850
Reason (R): For any three numbers x, y and z : x × (y - z) = x × y - x × z the multiplication is distributive over subtraction.
1A is true, R is false.
2A is false, R is true.
3Both A and R are true.
4Both A and R are false.
View step-by-step answerOpen
Assertion (A): Using the distributive law, 656 × 42 - 656 × 17 = 656 × (42 - 17) = 656 × 25 = 16400, not 9850. So, the assertion is false.

Reason (R): For any three numbers x, y and z, x × (y - z) = x × y - x × z, which is the distributive property of multiplication over subtraction. So, the reason is true.

A is false and R is true.

Hence, option 2 is the correct option.

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Frequently Asked Questions

What is the difference between natural numbers and whole numbers?

Natural numbers begin with 1, while whole numbers begin with 0. Every natural number is a whole number, but 0 is a whole number that is not a natural number.

What is the smallest natural number?

The smallest natural number is 1.

What is the smallest whole number?

The smallest whole number is 0.

Do natural numbers and whole numbers have a largest number?

No. Both sets continue without end, so neither has a largest number.

How do we find the successor and predecessor of a number?

Add 1 to find the successor and subtract 1 to find the predecessor.

What is the distributive property of multiplication?

Multiplication distributes over addition and subtraction: a times the sum or difference of two numbers equals the sum or difference of the two separate products.

Why is division by zero not defined?

There is no number that can be multiplied by zero to produce a non-zero dividend, so division by zero is not defined.

Concept by Teacher Ritu, designed by Shaleen Shekhar.

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