The Mystery of Floating Objects!
Upthrust in Fluids and Archimedes' Principle
🚢 💧 ⚖️ 🧪
Can a heavy iron ship float while a tiny iron nail sinks?
Can water make a heavy stone appear lighter?
Discover the answers through experiments, analytical questions and real-life challenges.
Welcome to SpeedUpScience!
1. Learning Objectives
By the end of this lesson, you will be able to:
- Define upthrust and buoyant force.
- Explain the origin and direction of upthrust in a fluid.
- State Archimedes' principle.
- Calculate upthrust using the volume and density of a displaced fluid.
- Explain apparent loss of weight in a liquid.
- Distinguish between actual weight and apparent weight.
- Analyse the conditions under which an object floats or sinks.
- Apply the principle of flotation to everyday situations.
- Solve numerical problems involving upthrust and displaced liquids.
- Develop scientific reasoning through competency-based questions.
2. A Small Story: The Stone That Became Lighter!
One afternoon, Aarav visited a science laboratory with his classmates.
His teacher suspended a heavy stone from a spring balance. The balance showed a reading of 10 N.
Then she slowly lowered the stone into a beaker of water without allowing it to touch the bottom.
Something surprising happened. The reading decreased to 7 N!
"Ma'am, has the stone lost some of its weight?" Aarav asked.
"No," replied the teacher. "Its weight due to gravity has not changed. Water is exerting an upward force on it."
The teacher explained that this upward force is called upthrust. She also showed the class how the weight of the displaced water could be used to calculate it.
Aarav then understood how the same principle explains floating ships, submarines and hydrometers.
The discovery: An observation becomes a scientific explanation when we connect it to evidence and a physical principle.
Story-Based Questions
- Why did the spring balance reading decrease?
- Did the actual weight of the stone change?
- Calculate the upthrust acting on the stone.
- Which scientific principle explains the relationship between upthrust and displaced water?
Reveal the answers
1. Water exerted an upward force on the immersed stone.
2. No. Its actual weight remained unchanged.
3. Upthrust = 10 − 7 = 3 N.
4. Archimedes' principle.
3. What Is Upthrust?
Upthrust is the upward force exerted by a fluid on a body wholly or partially immersed in it.
A fluid can be a liquid, such as water, or a gas, such as air.
Why Does Upthrust Act?
Pressure in a liquid increases with depth. Therefore, the lower surface of an immersed object generally experiences greater pressure than its upper surface.
The resulting pressure difference produces a net upward force called upthrust.
Important Characteristics
- Upthrust acts vertically upwards.
- It opposes the weight of an object.
- It acts on immersed objects whether they float or sink.
- Its magnitude depends on the density of the fluid and the volume of fluid displaced.
- Its SI unit is the newton (N).
Try This Investigation!
Take a stone, a spring balance and a container of water.
- Measure the weight of the stone in air.
- Immerse the stone completely in water.
- Observe the new spring balance reading.
- Subtract the immersed reading from the reading in air.
The difference gives the upthrust, assuming the stone does not touch the container and other effects are negligible.
Upthrust = Weight in air − Apparent weight in liquid
4. Archimedes' Principle
Archimedes' principle states:
When a body is wholly or partially immersed in a fluid, it experiences an upthrust equal to the weight of the fluid displaced by it.
Mathematically:
Where:
- U = upthrust in newtons (N)
- ρ = density of the fluid in kg/m³
- V = volume of fluid displaced in m³
- g = acceleration due to gravity in m/s²
Three Important Ideas
1. An object completely immersed in a fluid displaces a volume of fluid equal to its own volume.
2. A partially immersed object displaces a volume of fluid equal to the volume of its submerged portion.
3. For a floating object at rest, the upthrust equals the weight of the object.
5. Apparent Loss of Weight
When an object is immersed in a liquid, the liquid exerts an upward force on it. The object therefore appears lighter.
Worked Example
A metal block weighs 25 N in air and 18 N when immersed completely in water.
Calculate its upthrust.
Upthrust = 25 − 18
Answer: 7 N
According to Archimedes' principle, the weight of the displaced water is also 7 N.
Remember
The object does not lose mass when immersed in water. Its actual gravitational weight remains unchanged, but its apparent weight decreases because of upthrust.
6. Why Do Objects Float or Sink?
| Situation | Scientific Explanation |
|---|---|
| Object less dense than the fluid | It can float partially submerged. |
| Object denser than the fluid | It sinks when released under ordinary conditions. |
| Object has the same average density as the fluid | It can remain suspended when fully immersed and in equilibrium. |
| Object floating at rest | Upthrust equals the object's weight. |
The Iron Ship Mystery
A solid iron nail sinks, but a hollow iron ship floats.
Why?
A ship has a hollow structure containing air. Its average density is sufficiently low for it to displace enough water to balance its weight.
The shape and total volume of the ship allow it to displace a large volume of water before becoming fully submerged.
7. Textbook-Based MCQs
These questions follow the concepts and question patterns in your uploaded ICSE textbook exercise.
Your Textbook Practice Report
8. Analytical Questions: Think Beyond the Textbook
Question 1: Two Identical Stones
Two identical stones are immersed completely in water. One is placed near the surface and the other at a greater depth.
Will the upthrust on them differ? Explain your reasoning.
Reveal the answer
Assuming water density remains constant and both stones are fully immersed, the upthrusts are equal because both displace equal volumes of water.
Upthrust depends on the weight of displaced fluid, not simply on depth.
Question 2: The Heavier Object
Two objects of different masses have equal volumes. Both are completely immersed in the same liquid.
Which object experiences greater upthrust?
Reveal the answer
Both experience equal upthrust because they displace equal volumes of the same liquid.
The heavier object has greater weight, but that does not mean it experiences greater upthrust.
Question 3: Water or Glycerine?
The same object is completely immersed in water and then in glycerine. Assume glycerine is denser than water.
In which liquid is the apparent weight smaller?
Reveal the answer
In glycerine, because it exerts greater upthrust for the same displaced volume. The greater upthrust produces a smaller apparent weight.
Question 4: A Floating Block
A wooden block floats with 60% of its volume submerged in water.
What can you conclude about its density compared with the density of water?
Reveal the answer
For a floating block:
Density of block ÷ Density of water = Fraction submerged.
Therefore, the density of the block is 0.60 times the density of water.
If water has a density of 1000 kg/m³, the block's density is 600 kg/m³.
Question 5: The Disappearing Weight
A body weighs 40 N in air and 28 N when immersed completely in a liquid.
Calculate the upthrust and state what the result tells you about the weight of the displaced liquid.
Reveal the answer
Upthrust = 40 − 28 = 12 N.
By Archimedes' principle, the weight of the displaced liquid is also 12 N.
Question 6: The Floating Ship
A ship is carrying cargo and floating safely. More cargo is loaded onto it.
Explain why the ship sinks deeper into the water.
Reveal the answer
Additional cargo increases the total weight of the ship. To balance this greater weight, the ship must displace more water, producing greater upthrust.
The ship sinks deeper until the upthrust balances the new total weight, provided it remains within safe loading limits.
9. Competency-Based Case Study: The Spring Balance Investigation
A student performs an experiment using a metal object, a spring balance and a beaker of water.
| Observation | Reading |
|---|---|
| Weight in air | 15 N |
| Apparent weight in water | 11 N |
Answer the questions
1. Calculate the upthrust.
Show solution
Upthrust = Weight in air − Apparent weight in water
= 15 − 11
Answer: 4 N
2. What is the weight of the displaced water?
Show solution
By Archimedes' principle, the weight of displaced water equals the upthrust.
Answer: 4 N
3. What would happen to the apparent weight if the same object displaced an equal volume of a denser liquid?
Show answer
The apparent weight would be smaller because the denser liquid would exert greater upthrust.
4. Does the object's actual weight change when it is immersed?
Show answer
No. Its actual gravitational weight remains unchanged. The spring balance reading decreases because of upthrust.
10. Numerical Challenge: Apply the Formula
Problem 1
A body of volume 100 cm³ is completely immersed in water. Calculate the upthrust.
Density of water = 1000 kg/m³ and g = 10 m/s².
Reveal the solution
Convert volume into SI units:
100 cm³ = 100 × 10⁻⁶ m³ = 0.0001 m³.
U = ρVg
U = 1000 × 0.0001 × 10
Answer: 1 N
Problem 2
A solid object weighs 50 N in air and 30 N in water. Calculate:
a. Upthrust
b. Weight of displaced water
c. Apparent loss of weight
Reveal the solution
a. Upthrust = 50 − 30 = 20 N
b. Weight of displaced water = 20 N
c. Apparent loss of weight = 50 − 30 = 20 N
Problem 3
A body displaces 0.005 m³ of a liquid of density 800 kg/m³. Calculate the upthrust. Take g = 10 m/s².
Reveal the solution
U = ρVg
U = 800 × 0.005 × 10
Answer: 40 N
Problem 4
A wooden block of volume 0.003 m³ and mass 2 kg is placed in water. Will it float or sink?
Density of water = 1000 kg/m³ and g = 10 m/s².
Reveal the solution
Weight of the block = mg
= 2 × 10 = 20 N.
Maximum upthrust when fully immersed:
U = 1000 × 0.003 × 10 = 30 N.
Since the block's weight is less than the maximum available upthrust, it can float.
At floating equilibrium, it displaces water weighing 20 N.
Volume submerged = 20 ÷ (1000 × 10)
= 0.002 m³.
Answer: It floats with two-thirds of its volume submerged.
11. Thinking-Based MCQs: Challenge Your Brain!
These questions require analysis and application. Read carefully before selecting an answer.
10 questions | 1 mark each
Your Analytical Thinking Report
12. Values We Learn Through Science
Curiosity
Ask questions about everyday observations instead of accepting them without investigation.
Logical Thinking
Use evidence, measurements and scientific principles to reach conclusions.
Responsibility
Understand why safe loading limits are important for ships and boats.
Care for Nature
Protect rivers, lakes and oceans because healthy aquatic environments support life.
Perseverance
When a numerical problem seems difficult, identify the known quantities, choose the correct formula and solve it step by step.
13. The Final Scientist Challenge
Can You Solve This Without Help?
A metal object weighs 60 N in air. When fully immersed in water, its apparent weight is 45 N.
The density of water is 1000 kg/m³ and g = 10 m/s².
Answer all four questions.
- Calculate the upthrust.
- Calculate the weight of water displaced.
- Calculate the volume of water displaced.
- Would the same object experience greater or smaller upthrust in a liquid denser than water, assuming it displaces the same volume?
Reveal the complete solution
1. Upthrust
U = 60 − 45 = 15 N.
2. Weight of displaced water
By Archimedes' principle, it is equal to the upthrust.
Answer = 15 N.
3. Volume displaced
U = ρVg
V = U ÷ ρg
V = 15 ÷ (1000 × 10)
Answer = 0.0015 m³, or 1500 cm³.
4. In a denser liquid
The upthrust will be greater because the same displaced volume of a denser liquid has greater weight.
14. Quick Revision
- Upthrust is the upward force exerted by a fluid on an immersed body.
- Upthrust occurs because fluid pressure differs across the body's surfaces.
- Archimedes' principle: Upthrust equals the weight of fluid displaced.
- Upthrust = ρVg.
- Apparent weight = Actual weight − Upthrust.
- For a fully immersed body, displaced fluid volume equals the body's volume.
- A floating object at rest has upthrust equal to its weight.
- A body less dense than a fluid can float partially submerged.
- Objects of equal volume, fully immersed in the same fluid, experience equal upthrust.
- A hydrometer works on the principle of flotation.
- A ship floats because it displaces enough water to balance its weight.
Think. Analyse. Discover!
Physics is not just about memorising formulas. It is about understanding why things happen.
Observe carefully. Question logically. Explain scientifically.
SpeedUpScience.com
Making Physics simple, interesting and meaningful!
0 Comments