🌈 Moment of Force (ICSE Class 10)
- Turning effect of force about pivot
- Produces rotational motion
- Examples: door, steering, spanner
- Fixed point of rotation
- Examples: hinge, see-saw, axle
- Greater distance → easier rotation
- M = F × d
- F → Applied force
- d → Perpendicular distance
- Magnitude of force
- Distance from pivot
- Greater values → greater turning effect
- Clockwise → Negative
- Anticlockwise → Positive
- Example: see-saw
- Clockwise moments = Anticlockwise moments
- Balanced body remains in equilibrium
- Applications: beam balance, weighing machine
- Two equal opposite parallel forces
- Produces rotation only
- Examples: steering wheel, bottle cap
🎯 Learning Objectives
- Understand turning effect of force.
- Learn rotational equilibrium.
- Apply moment concepts in daily life.
🧩 Competencies
- Conceptual Understanding
- Analytical Thinking
- Problem Solving
📊 Learning Outcomes
- Defines moment of force correctly.
- Uses formula to solve problems.
- Identifies clockwise and anticlockwise moments.
📌 Evidence
- MCQ performance
- Numerical solving
- Classroom discussion
🌈 Moment of Force - Quiz, HOTS & Numericals
📝 MCQ Quiz
🧠 HOTS Questions
1. Why is door handle fixed away from hinges?
Greater distance from pivot increases turning effect.
2. Why can small force rotate body if distance is large?
Moment depends on both force and perpendicular distance.
3. Why is see-saw balanced?
Clockwise moments become equal to anticlockwise moments.
4. Why does steering wheel have circular shape?
Larger radius increases turning effect.
5. Can a couple move a body in straight line?
No, a couple produces only rotational motion.
🔢 Simple Numericals
1. A force of 10 N acts at a distance of 2 m from pivot. Find moment of force.
Formula:
M = F × d
M = 10 × 2
Moment = 20 Nm
2. A force of 5 N acts at 4 m distance. Find turning effect.
M = F × d
M = 5 × 4
Moment = 20 Nm
3. A moment of 30 Nm is produced by force 6 N. Find distance.
M = F × d
30 = 6 × d
d = 30 ÷ 6
Distance = 5 m
