Exercise 1(A) — Multiple Choice Type
Question
1
The
condition(s) essential for a unit to be accepted internationally :
- The unit should be of convenient
size and without any ambiguity.
- The unit should be reproducible.
- The value of the unit should not
change with space and time.
- All of the above.
Answer
All
of the above
Question
2
In
mechanics, the three fundamental quantities are:
- Length, mass, velocity
- Mass, time, density
- Mass, time, pressure
- Length, mass, time
Answer
Length,
mass, time
How
many units are fundamental and complementary?
- 2 fundamental, 7 complementary
- 3 fundamental, 6 complementary
- 7 fundamental, 2 complementary
- 4 fundamental, 5 complementary
Answer
7
fundamental, 2 complementary
Question
4
The
fundamental unit is —
- newton
- pascal
- hertz
- second
Answer
second
Question
5
Which
of the following unit is not a fundamental unit:
- metre
- litre
- second
- Kilogram
Answer
Litre
Reason — Metre, second and kilogram
are the fundamental units whereas litre is a derived unit.
Question
6
One
millimeter is ............... part of a metre:
- One hundredth
- One thousandth
- One billionth
- One millionth
Answer
One thousandth
Question
7
One
astronomical unit is equal to:
- 1.496 x 1011 metre
- 1.596 x 1012 metre
- 1.498 x 1010 metre
- 1.398 x 1011 metre
Answer
1.496
x 1011 metre
Question 8
The
distance of stars from earth is generally measured in:
- Kilometre
- Light year
- Angstrom
- Fermi
Answer
Light year
Question
9
1
Fermi is equal to:
- 10-14 m
- 10-10 m
- 1015 m
- 10-15 m
Answer
10-15 m
Question
10
The
unit of time is:
- light year
- parsec
- leap year
- angstrom
Answer
leap year
Question
11
1 Ã…
is equal to:
- 0.1 nm
- 10-10cm
- 10-8m
- 104µ
Answer
0.1 nm
One
metric tonne is equal to :
- 10 quintal
- 100 quintal
- 1000 quintal
- 25 quintal
Answer
10 quintal
Question
13
Light-year
is the unit of:
- Time
- Length
- Mass
- none of these
Answer
Length
Question
14
One
solar mass is equal to :
- 3 x 1020 kg
- 2 x 1027 kg
- 2 x 1030 kg
- 3 x 1030 kg
Answer
2 x 1030 kg
Question
15
One
lunar cycle is nearly equal to:
- 28.5 days
- 29.5 days
- 30 days
- 30.5 days
Answer
29.5 days
Question
16
One
shake is equal to:
- 10-9 s
- 10-8 s
- 10-10 s
- 108 s
Answer
10-8 s
Question
17
Which
of the following unit is equivalent to watt?
- volt x ampere
- volt/ampere
- ampere/volt
- Ohm
Answer
volt x ampere
Question
18
Which
one of the following is a derived unit?
- metre
- kelvin
- metre3
- mole
Answer
metre3
Question
19
The
S.I. unit of energy is:
- joule
- Kg m2
- Kg m2s-3
- Kg m2s-1
Answer
joule
Question
20
The
S.I. unit of pressure is:
- Kg m-2s-2
- Kg m-1s-2
- Kg m2
- Kg ms-2
Answer
Kg m-1s-2
Question
21
Which
of the following is the smallest unit?
- millimetre
- Angstrom
- Fermi
- metre
Answer
Fermi
Reason — Fermi is 10-15th
part of a metre. i.e., 1 fermi = 10-15 m, hence it is the
smallest unit.
Angstrom
= 10-10th part of a metre.
Millimetre = 10-3th part of a metre.
Exercise 1(A) — Very Short Answer Type
Question
1
What
is meant by measurement?
Answer
Measurement
is the process of comparison of the given quantity with the known standard
quantity of the same nature.
Question
2
What
do you understand by the term unit?
Answer
Unit
is the quantity of a constant magnitude which is used to measure the magnitudes
of other quantities of the same nature.
Question
3
How
is a physical quantity expressed?
Answer
A
physical quantity is expressed in terms of the following parameters:
- The unit in which the quantity is
being measured, and
- The numerical value which expresses,
how many times the above selected unit is contained in the given quantity.
Thus,
the magnitude of physical quantity is expressed as : Physical quantity =
(numerical value) x (unit)
Question
4
Name
the three fundamental quantities.
Answer
The
three fundamental quantities are —
- Mass
- Length
- Time
Question
5
What
is the S.I. unit of Luminous intensity?
Answer
The
S.I. unit of Luminous intensity is candela (cd).
Question
6
Define
one parsec.
Answer
One
parsec is the distance from where the semi major axis of orbit of earth (1
A.U.) subtends an angle of one second.
Question
7
Define
a fundamental unit.
Answer
A
fundamental unit is that which is independent of any other unit or which can
neither be changed nor can be related to any other fundamental unit.
Example
– Units of mass, length, time, temperature, current etc.
Question
8
Define
a derived unit.
Answer
Derived
units are those which depend on the fundamental units or which can be expressed
in terms of fundamental units.
Example:
For the measurement of area, we need to measure length and breadth in the unit
of length and then express area in a unit which is length x length or (length)2
Question
9
Define
standard metre.
Answer
The
standard metre is defined in terms of speed of light, according to which, one
metre is the distance travelled by light in 1/299,792,458 of a second in air
(or vacuum).
Question
10
How
is nanometer related to Angstrom ?
Answer
Relation
between nanometer (nm) and Angstrom (Ã…) is expressed as:
1 nanometer = 10 Ã…
Question
11
Complete
the following —
- 1 light year = ________ m
- 1 m = ________ Ã…
- 1 m = ________ µ
- 1 micron = ________ Ã…
- 1 fermi = ________ m
Answer
- 1 light year = 9.46 x 1015 m
- 1 m = 1010 Ã…
- 1 m = 106 µ
- 1 micron = 104 Ã…
- 1 fermi = 10-15 m
Question
12
Complete
the following —
- 1g = ______kg
- 1mg = ________kg
- 1 quintal = ________kg
- 1 a.m.u (or u) = ________kg
Answer
- 1 g = 10-3 kg
- 1 mg = 10-6 kg
- 1 quintal = 100 kg
- 1 a.m.u (or u) = 1.66 x 10-27 kg
Question
13
What
is a leap year?
Answer
A
leap year is the year in which the month of February is of 29 days.
1
Leap year = 366 days
Every
fourth year (i.e., the year divisible by 4) has one day extra in the month of
february (i.e., February has 29 days) and so it is the leap year.
Question
14
'The
year 2024 will have February of 29 days'. Is this statement true?
Answer
Yes
the statement is true.
We
know that, if any year is divisible by 4, then it is a leap year and in a leap
year, February has 29 days. As, the year 2024 is divisible by 4, so it will
have 29 days in February.
Question
15
What
is a lunar month?
Answer
A
lunar month is the time of one lunar cycle, i.e., it is the amount of time it
takes for the Moon to complete one orbit around the Earth and it is nearly
equal to 29.5 days.
Question
16
Complete
the following —
- 1 nano second = ________s
- 1 µs = _______s
- 1 mean solar day = ________s
- 1 year = ________s
Answer
- 1 nano second = 10-9 s
- 1 µs = 10-6 s
- 1 mean solar day = 86400 s
- 1 year = 3.15 x 107 s
Question
17
Name
the physical quantities which are measured in the following units —
- u
- ly
- ns
- nm
Answer
Physical
quantity related to the unit are as follows —
Unit |
Physical quantity |
u |
Mass |
ly |
Distance |
ns |
Time |
nm |
Length |
Question
18
Write
the derived units of the following —
- Speed
- Force
- Work
- Pressure
Answer
The
derived units of the following quantities are as follows —
Quanity |
Derived unit |
Speed |
m/s |
Force |
kg m /s² |
Work |
kg m²/s² |
Pressure |
kg/ ms² |
Question
19
How
are the following derived units related to the fundamental units?
- newton
- watt
- joule
- pascal
Answer
Derived unit |
Fundamental unit |
newton |
kg m /s² |
watt |
kg m2/s³ |
joule |
kg m²/s² |
pascal |
kg /m¹s² |
Question
20
Name
the physical quantities related to the following units —
- km2
- newton
- joule
- pascal
- watt
Answer
The
physical quantities related to the following units are —
Unit |
Physical quantity |
km2 |
area |
newton |
force |
joule |
energy |
pascal |
pressure |
watt |
power |
Exercise 1(A) — Short Answer Type
Question
1
What
are the three requirements for selecting a unit of a physical quantity?
Answer
The
three requirements for selecting a unit of a physical quantity are —
- The unit should be of convenient
size.
- It should be possible to define the
unit without any ambiguity.
- The unit should be reproducible.
- The value of unit should not change
with space and time. (i.e. it must always remain same everywhere).
Question
2
What
are the fundamental units in S.I. system? Name them along with their symbols.
Answer
The
fundamental units in S.I. system along with their symbols are as follows —
Quantity |
Unit |
Symbol |
Length |
metre |
m |
Mass |
kilogram |
kg |
Time |
second |
s |
Temperature |
kelvin |
K |
Luminous intensity |
candela |
cd |
Electric current |
ampere |
A |
Amount of substance |
mole |
mol |
Angle |
radian |
rd |
Solid angle |
steradian |
st-rd |
Question
3
Explain
the meaning of derived unit with the help of one example.
Answer
The
units of quantities other than those measured in fundamental units, can be
expressed in terms of the fundamental units and they are called derived units.
Thus,
derived units are those which depend on the fundamental units or which can be
expressed in terms of the fundamental units.
Example
– For the measurement of area, we need to measure length and breadth in the
unit of length and then express area in a unit which is:
length
x length or (length)2.
Question
4
Name
two units of length which are bigger than a metre. How are they related to the
metre?
Answer
The
units of length which are bigger than a metre are —
- Astronomical Unit (A.U.) — One astronomical unit is equal to the mean distance
between the earth and the sun. Relation between metre and astronomical
unit is expressed as:
A.U. = 1.496 x 1011m - Light year (ly) — A light year is the distance travelled by light in
vacuum, in one year. Relation between metre and light year is expressed
as:
1 light year = 9.46 x 1015m
Question
5
Name
the three convenient units used to measure length ranging from very short to
very long value. How are they related to the S.I. unit ?
Answer
The
3 convenient units used to measure length ranging from very short to very long
value are —
- centimetre (cm)
- metre (m)
- kilometer (km)
S.I.
unit of length is meter (m). Relation between meter (m) and centimetre is —
1
m = 100 cm
Relation
between metre (m) and kilometre is —
1
km = 1000 m
Question
6
Name
the S.I. unit of mass and define it.
Answer
The
S.I. unit of mass is kilogram (Kg).
One
kilogram is defined as the mass of a cylindrical piece of platinum-iridium
alloy kept at International Bureau of Weights and Measures at Serves near
Paris.
Question
7
State
two units of mass smaller than a kilogram. How are they related to kilogram ?
Answer
The
two units of mass smaller than a kilogram (kg) are:
- gram (g) — Relation
between gram and kilogram is:
1 g = 10-3 kg - milligram (mg) — Relation between miligram and kilogram is:
1 mg = 10-6 kg
Question
8
State
two units of mass bigger than a kilogram. Give their relationship with the
kilogram.
Answer
The
two units of mass bigger than a kilogram (kg) are:
- quintal — It is one
hundred times a kilogram. Relation between quintal and kilogram is:
1 quintal = 100 kg - metric tonne — It is one thousand times a kilogram. Relation between
metric tonne and kilogram is:
1 metric tonne = 1000 kg
Question
9
Name
the S.I. unit of time and define it.
Answer
The
S.I. unit of time is second (s).
A second can be defined as 1/86400th part of a mean solar day.
Question
10
Name
two units of time bigger than a second. How are they related to second?
Answer
The
two units of time bigger than a second (s) are:
- minute (min) — One minute is the duration of 60 seconds. Relation
between minute and second is:
1 min = 60s - hour (h) — One hour
is the duration of 60m minutes. Relation between hour and second is:
1 h = 3600s
Exercise 1(A) — Numericals
Question
1
The
wavelength of light of a particular colour is 5800 Ã….
Express
it in —
(a)
nanometer and
(b)
metre
Answer
As
we know, 1nm = 10 Ã…
Given,
The
wavelength of light = 5800 Ã…
Substituting the value of wavelength in the relation
10 Ã… = 1nm
1Ã… = 0.1nm
5800 Ã… = 5800 x 0.1nm
Hence, wavelength
of 5800 Ã… in nm = 580 nm.
(b)
As we know,
1m = 1010 Ã…
Given,
The
wavelength of light = 5800 Ã…
Substituting
the value of wavelength in the relation above, we get,
Hence, wavelength
of 5800 Ã… in m = 5.8 x 10 -7m.
Question
2
The
size of a bacteria is 1 µ. Find the number of bacteria in 1m length.
Answer
Given,
Size
of a bacteria = 1 µ
Total
length = 1m
As
we know, 1 µ = 10-6m, substituting the value in the relation above
we get:
Number
of bacteria in 1m length = 10⁶
Hence,
number of bacteria in 1m length = 106 bacteria.
Question
3
The
distance of a galaxy from the earth is 5.6 x 1025m. Assuming the
speed of light to be 3 x 108 m/s . Find the time taken by light
to travel this distance.
Answer
Given,
Time taken=distance/ speed
distance
= 5.6 x 1025m
speed
= 3 x 108 m/s
Substituting
the values in the formula above we get,
∴, time taken by light
= 1.87 x 1017s.
Question
4
The
wavelength of light is 589nm. What is its wavelength in Ã…?
Answer
As
we know, 1nm = 10 Ã…
Given,
The wavelength
of light = 589nm
Substituting
the value of wavelength in the relation above, we get,
Hence, the
wavelength of light in Ã… is 5890 Ã….
Question
5
The
distance of the nearest star, Proxima Centauri, from the Earth is 4.0 x 1013 km.
Express it in light year.
Answer
1
Light year = 9.46 x 1012 km
or
9.46 x 1012 km = 1light year
1 km = (1 ÷ 9.46 x 10¹²) light year
4.0 x 1013 km =( 4.0 x 1013 ÷ 9.46 x 10¹²) light year
=
4.2 light years.
Hence, distance
of the nearest star from earth = 4.2 light years.
Question
6
It
takes time 8 min for light to reach from the sun to the earth surface. If speed
of light is taken to be 3 x 108m/s, find the distance
from the sun to the earth in km.
Answer
As
we know, Distance = speed x time
Given,
Speed
= 3 x 108m/s
Time
= 8 min = 8 x 60s = 480s
Substituting
the values in the formula above we get,
Distance
= 3 x 108 x 480 = 1440 x 108 m.
Converting
the distance to km:
Distance = 1.44 x 108 km
∴,
the distance from the sun to the earth is 1.44 x 108 km.
Question
7
'The
distance of a star from the earth is 8.33 light minutes'. What do you mean by
this statement? Express the distance in metre.
Answer
'The
distance of a star from the earth is 8.33 light minutes' implies, it takes 8.33
minutes for light to reach the earth from the star.
As
we know,
Distance = speed x time
Given,
Speed
= 3 x 108ms-1
Time
= 8.33 min
= 8.33 x 60s
= 499.8s
≈ 500s
Substituting
the values in the formula above we get,
Distance
= 3 x 108 x 500
= 1500 x 108
= 1.5 x 1011
∴, the distance from
the star to the earth is 1.5 x 1011 m.